Base | Representation |
---|---|
bin | 111101111100101001… |
… | …0111111100011111001 |
3 | 110201101012021122120202 |
4 | 1323321102333203321 |
5 | 4134422032241401 |
6 | 141040331131545 |
7 | 12416434205333 |
oct | 1737122774371 |
9 | 421335248522 |
10 | 133031524601 |
11 | 51466911468 |
12 | 21947ba3bb5 |
13 | c710c75c81 |
14 | 661dd5a453 |
15 | 36d908306b |
hex | 1ef94bf8f9 |
133031524601 has 2 divisors, whose sum is σ = 133031524602. Its totient is φ = 133031524600.
The previous prime is 133031524471. The next prime is 133031524603. The reversal of 133031524601 is 106425130331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123305620201 + 9725904400 = 351149^2 + 98620^2 .
It is a cyclic number.
It is not a de Polignac number, because 133031524601 - 210 = 133031523577 is a prime.
Together with 133031524603, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (133031524603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515762300 + 66515762301.
It is an arithmetic number, because the mean of its divisors is an integer number (66515762301).
Almost surely, 2133031524601 is an apocalyptic number.
It is an amenable number.
133031524601 is a deficient number, since it is larger than the sum of its proper divisors (1).
133031524601 is an equidigital number, since it uses as much as digits as its factorization.
133031524601 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 133031524601 its reverse (106425130331), we get a palindrome (239456654932).
The spelling of 133031524601 in words is "one hundred thirty-three billion, thirty-one million, five hundred twenty-four thousand, six hundred one".
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