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133031525141 is a prime number
BaseRepresentation
bin111101111100101001…
…0111111101100010101
3110201101012021200022202
41323321102333230111
54134422032301031
6141040331134245
712416434210034
oct1737122775425
9421335250282
10133031525141
1151466911909
1221947ba4385
13c710c762a8
14661dd5a71b
1536d90832cb
hex1ef94bfb15

133031525141 has 2 divisors, whose sum is σ = 133031525142. Its totient is φ = 133031525140.

The previous prime is 133031525131. The next prime is 133031525171. The reversal of 133031525141 is 141525130331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125844724516 + 7186800625 = 354746^2 + 84775^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133031525141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133031525131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515762570 + 66515762571.

It is an arithmetic number, because the mean of its divisors is an integer number (66515762571).

Almost surely, 2133031525141 is an apocalyptic number.

It is an amenable number.

133031525141 is a deficient number, since it is larger than the sum of its proper divisors (1).

133031525141 is an equidigital number, since it uses as much as digits as its factorization.

133031525141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 133031525141 its reverse (141525130331), we get a palindrome (274556655472).

The spelling of 133031525141 in words is "one hundred thirty-three billion, thirty-one million, five hundred twenty-five thousand, one hundred forty-one".