Base | Representation |
---|---|
bin | 111101111100101001… |
… | …0111111101100001011 |
3 | 110201101012021200022101 |
4 | 1323321102333230023 |
5 | 4134422032301011 |
6 | 141040331134231 |
7 | 12416434210021 |
oct | 1737122775413 |
9 | 421335250271 |
10 | 133031525131 |
11 | 514669118aa |
12 | 21947ba4377 |
13 | c710c7629b |
14 | 661dd5a711 |
15 | 36d90832c1 |
hex | 1ef94bfb0b |
133031525131 has 2 divisors, whose sum is σ = 133031525132. Its totient is φ = 133031525130.
The previous prime is 133031524897. The next prime is 133031525141. The reversal of 133031525131 is 131525130331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133031525131 is a prime.
It is a super-2 number, since 2×1330315251312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 133031525131.
It is not a weakly prime, because it can be changed into another prime (133031525141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515762565 + 66515762566.
It is an arithmetic number, because the mean of its divisors is an integer number (66515762566).
Almost surely, 2133031525131 is an apocalyptic number.
133031525131 is a deficient number, since it is larger than the sum of its proper divisors (1).
133031525131 is an equidigital number, since it uses as much as digits as its factorization.
133031525131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4050, while the sum is 28.
Adding to 133031525131 its reverse (131525130331), we get a palindrome (264556655462).
The spelling of 133031525131 in words is "one hundred thirty-three billion, thirty-one million, five hundred twenty-five thousand, one hundred thirty-one".
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