Base | Representation |
---|---|
bin | 1100000110010110010010… |
… | …1101000010100100111111 |
3 | 1202002202220002220020012021 |
4 | 3001211210231002210333 |
5 | 3220424430012304401 |
6 | 44143223542221011 |
7 | 2542060530555616 |
oct | 301454455024477 |
9 | 52082802806167 |
10 | 13303203244351 |
11 | 4269947465979 |
12 | 15aa2bba24767 |
13 | 756643320487 |
14 | 33dc4275887d |
15 | 1810a81852a1 |
hex | c1964b4293f |
13303203244351 has 2 divisors, whose sum is σ = 13303203244352. Its totient is φ = 13303203244350.
The previous prime is 13303203244291. The next prime is 13303203244381. The reversal of 13303203244351 is 15344230230331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13303203244351 - 213 = 13303203236159 is a prime.
It is a super-2 number, since 2×133032032443512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13303203244381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651601622175 + 6651601622176.
It is an arithmetic number, because the mean of its divisors is an integer number (6651601622176).
Almost surely, 213303203244351 is an apocalyptic number.
13303203244351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13303203244351 is an equidigital number, since it uses as much as digits as its factorization.
13303203244351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 13303203244351 its reverse (15344230230331), we get a palindrome (28647433474682).
The spelling of 13303203244351 in words is "thirteen trillion, three hundred three billion, two hundred three million, two hundred forty-four thousand, three hundred fifty-one".
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