Base | Representation |
---|---|
bin | 11110001111111001101110… |
… | …000110011111010110101111 |
3 | 122110000221102122021211101202 |
4 | 132033321232012133112233 |
5 | 114414112432020040414 |
6 | 1150535015031200115 |
7 | 40010254415101502 |
oct | 3617715606372657 |
9 | 573027378254352 |
10 | 133034164221359 |
11 | 39430521567095 |
12 | 12b06ab451603b |
13 | 59300b610988b |
14 | 24bcc605a1139 |
15 | 105a7cd2c99de |
hex | 78fe6e19f5af |
133034164221359 has 2 divisors, whose sum is σ = 133034164221360. Its totient is φ = 133034164221358.
The previous prime is 133034164221341. The next prime is 133034164221367. The reversal of 133034164221359 is 953122461430331.
It is a strong prime.
It is an emirp because it is prime and its reverse (953122461430331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133034164221359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133034164221559) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66517082110679 + 66517082110680.
It is an arithmetic number, because the mean of its divisors is an integer number (66517082110680).
Almost surely, 2133034164221359 is an apocalyptic number.
133034164221359 is a deficient number, since it is larger than the sum of its proper divisors (1).
133034164221359 is an equidigital number, since it uses as much as digits as its factorization.
133034164221359 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1399680, while the sum is 47.
The spelling of 133034164221359 in words is "one hundred thirty-three trillion, thirty-four billion, one hundred sixty-four million, two hundred twenty-one thousand, three hundred fifty-nine".
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