Base | Representation |
---|---|
bin | 11000110001111001… |
… | …00010010010000011 |
3 | 1021100010201222010021 |
4 | 30120330202102003 |
5 | 204221134033011 |
6 | 10040030314311 |
7 | 650446145044 |
oct | 143074422203 |
9 | 37303658107 |
10 | 13303424131 |
11 | 57074884a8 |
12 | 26b3358997 |
13 | 13401cb1ca |
14 | 902b908cb |
15 | 52cdda471 |
hex | 318f22483 |
13303424131 has 2 divisors, whose sum is σ = 13303424132. Its totient is φ = 13303424130.
The previous prime is 13303424129. The next prime is 13303424221. The reversal of 13303424131 is 13142430331.
It is a weak prime.
It is an emirp because it is prime and its reverse (13142430331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13303424131 - 21 = 13303424129 is a prime.
It is a super-2 number, since 2×133034241312 (a number of 21 digits) contains 22 as substring.
Together with 13303424129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13303424096 and 13303424105.
It is not a weakly prime, because it can be changed into another prime (13303424231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651712065 + 6651712066.
It is an arithmetic number, because the mean of its divisors is an integer number (6651712066).
Almost surely, 213303424131 is an apocalyptic number.
13303424131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13303424131 is an equidigital number, since it uses as much as digits as its factorization.
13303424131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13303424131 its reverse (13142430331), we get a palindrome (26445854462).
The spelling of 13303424131 in words is "thirteen billion, three hundred three million, four hundred twenty-four thousand, one hundred thirty-one".
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