Base | Representation |
---|---|
bin | 10011010111000010000… |
… | …110110000000010001111 |
3 | 11201011222222000211012221 |
4 | 103113002012300002033 |
5 | 133244130232201413 |
6 | 2455102240040211 |
7 | 165055405455013 |
oct | 23270206600217 |
9 | 4634888024187 |
10 | 1330401443983 |
11 | 473246a28007 |
12 | 195a10903067 |
13 | 985c16b8151 |
14 | 4856b052543 |
15 | 24917dea68d |
hex | 135c21b008f |
1330401443983 has 2 divisors, whose sum is σ = 1330401443984. Its totient is φ = 1330401443982.
The previous prime is 1330401443981. The next prime is 1330401444011. The reversal of 1330401443983 is 3893441040331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330401443983 - 21 = 1330401443981 is a prime.
Together with 1330401443981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330401443981) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665200721991 + 665200721992.
It is an arithmetic number, because the mean of its divisors is an integer number (665200721992).
Almost surely, 21330401443983 is an apocalyptic number.
1330401443983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330401443983 is an equidigital number, since it uses as much as digits as its factorization.
1330401443983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 373248, while the sum is 43.
The spelling of 1330401443983 in words is "one trillion, three hundred thirty billion, four hundred one million, four hundred forty-three thousand, nine hundred eighty-three".
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