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133040431015571 is a prime number
BaseRepresentation
bin11110001111111111100011…
…101000011010011010010011
3122110001112121101100221221002
4132033333203220122122103
5114414213300314444241
61150541532534252215
740010565622006532
oct3617774350323223
9573045541327832
10133040431015571
1139433147a51362
1212b081631b706b
135930874548231
1424bd2969bc319
15105aa4856289b
hex78ffe3a1a693

133040431015571 has 2 divisors, whose sum is σ = 133040431015572. Its totient is φ = 133040431015570.

The previous prime is 133040431015501. The next prime is 133040431015573. The reversal of 133040431015571 is 175510134040331.

It is a strong prime.

It is an emirp because it is prime and its reverse (175510134040331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133040431015571 - 226 = 133040363906707 is a prime.

It is a super-2 number, since 2×1330404310155712 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 133040431015573, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133040431015573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66520215507785 + 66520215507786.

It is an arithmetic number, because the mean of its divisors is an integer number (66520215507786).

Almost surely, 2133040431015571 is an apocalyptic number.

133040431015571 is a deficient number, since it is larger than the sum of its proper divisors (1).

133040431015571 is an equidigital number, since it uses as much as digits as its factorization.

133040431015571 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75600, while the sum is 38.

The spelling of 133040431015571 in words is "one hundred thirty-three trillion, forty billion, four hundred thirty-one million, fifteen thousand, five hundred seventy-one".