Base | Representation |
---|---|
bin | 11110010000000010000110… |
… | …100110010110101010011110 |
3 | 122110001210122221010222220220 |
4 | 132100002012212112222132 |
5 | 114414234400240142032 |
6 | 1150543104124422210 |
7 | 40011023441611404 |
oct | 3620020646265236 |
9 | 573053587128826 |
10 | 133043165162142 |
11 | 39434320340124 |
12 | 12b087a69a7966 |
13 | 5930bbbb29141 |
14 | 24bd475b7d474 |
15 | 105ab585e012c |
hex | 790086996a9e |
133043165162142 has 64 divisors (see below), whose sum is σ = 273356443176960. Its totient is φ = 43144538220000.
The previous prime is 133043165162129. The next prime is 133043165162147. The reversal of 133043165162142 is 241261561340331.
It is a junction number, because it is equal to n+sod(n) for n = 133043165162094 and 133043165162103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133043165162147) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 72528417 + ... + 74340147.
It is an arithmetic number, because the mean of its divisors is an integer number (4271194424640).
Almost surely, 2133043165162142 is an apocalyptic number.
133043165162142 is an abundant number, since it is smaller than the sum of its proper divisors (140313278014818).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133043165162142 is a wasteful number, since it uses less digits than its factorization.
133043165162142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1812909.
The product of its (nonzero) digits is 311040, while the sum is 42.
The spelling of 133043165162142 in words is "one hundred thirty-three trillion, forty-three billion, one hundred sixty-five million, one hundred sixty-two thousand, one hundred forty-two".
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