Base | Representation |
---|---|
bin | 11000110010000000… |
… | …10001000110100101 |
3 | 1021100012120122222021 |
4 | 30121000101012211 |
5 | 204221411333331 |
6 | 10040103303141 |
7 | 650460361006 |
oct | 143100210645 |
9 | 37305518867 |
10 | 13304402341 |
11 | 5707a9643a |
12 | 26b374aab1 |
13 | 1340481529 |
14 | 902d671ad |
15 | 52d030211 |
hex | 3190111a5 |
13304402341 has 2 divisors, whose sum is σ = 13304402342. Its totient is φ = 13304402340.
The previous prime is 13304402291. The next prime is 13304402389. The reversal of 13304402341 is 14320440331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12887017441 + 417384900 = 113521^2 + 20430^2 .
It is a cyclic number.
It is not a de Polignac number, because 13304402341 - 223 = 13296013733 is a prime.
It is a super-3 number, since 3×133044023413 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13304402641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652201170 + 6652201171.
It is an arithmetic number, because the mean of its divisors is an integer number (6652201171).
Almost surely, 213304402341 is an apocalyptic number.
It is an amenable number.
13304402341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13304402341 is an equidigital number, since it uses as much as digits as its factorization.
13304402341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 13304402341 its reverse (14320440331), we get a palindrome (27624842672).
The spelling of 13304402341 in words is "thirteen billion, three hundred four million, four hundred two thousand, three hundred forty-one".
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