1330462220051 has 2 divisors, whose sum is σ = 1330462220052. Its totient is φ = 1330462220050.

The previous prime is 1330462220039. The next prime is 1330462220053. The reversal of 1330462220051 is 1500222640331.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1500222640331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1330462220051 - 2¹⁰ = 1330462219027 is a prime.

Together with 1330462220053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330462219996 and 1330462220023.

It is not a weakly prime, because it can be changed into another prime (1330462220053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665231110025 + 665231110026.

It is an arithmetic number, because the mean of its divisors is an integer number (665231110026).

Almost surely, 2^{1330462220051} is an apocalyptic number.

1330462220051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330462220051 is an equidigital number, since it uses as much as digits as its factorization.

1330462220051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1330462220051 its reverse (1500222640331), we get a palindrome (2830684860382).

The spelling of 1330462220051 in words is "one trillion, three hundred thirty billion, four hundred sixty-two million, two hundred twenty thousand, fifty-one".