Base | Representation |
---|---|
bin | 1111110111000… |
… | …10110010100011 |
3 | 100021100121121112 |
4 | 13323202302203 |
5 | 233030041012 |
6 | 21111413535 |
7 | 3203621303 |
oct | 773426243 |
9 | 307317545 |
10 | 133049507 |
11 | 69115078 |
12 | 386842ab |
13 | 21745826 |
14 | 13955603 |
15 | ba32122 |
hex | 7ee2ca3 |
133049507 has 2 divisors, whose sum is σ = 133049508. Its totient is φ = 133049506.
The previous prime is 133049461. The next prime is 133049513. The reversal of 133049507 is 705940331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133049507 - 210 = 133048483 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (133049537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66524753 + 66524754.
It is an arithmetic number, because the mean of its divisors is an integer number (66524754).
Almost surely, 2133049507 is an apocalyptic number.
133049507 is a deficient number, since it is larger than the sum of its proper divisors (1).
133049507 is an equidigital number, since it uses as much as digits as its factorization.
133049507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 32.
The square root of 133049507 is about 11534.7087956307. The cubic root of 133049507 is about 510.5101994142.
Adding to 133049507 its reverse (705940331), we get a palindrome (838989838).
The spelling of 133049507 in words is "one hundred thirty-three million, forty-nine thousand, five hundred seven".
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