Base | Representation |
---|---|
bin | 11110010000001000111110… |
… | …011011100010000011000110 |
3 | 122110002111201012022001101120 |
4 | 132100020332123202003012 |
5 | 114414400003320101410 |
6 | 1150550324245134410 |
7 | 40011404343343464 |
oct | 3620107633420306 |
9 | 573074635261346 |
10 | 133050544300230 |
11 | 39437467700857 |
12 | 12b0a1060ba406 |
13 | 59317c684ab3b |
14 | 24bd975bcd834 |
15 | 105ae3b34b570 |
hex | 79023e6e20c6 |
133050544300230 has 16 divisors (see below), whose sum is σ = 319321306320624. Its totient is φ = 35480145146720.
The previous prime is 133050544300207. The next prime is 133050544300277. The reversal of 133050544300230 is 32003445050331.
It is a junction number, because it is equal to n+sod(n) for n = 133050544300191 and 133050544300200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2217509071641 + ... + 2217509071700.
It is an arithmetic number, because the mean of its divisors is an integer number (19957581645039).
Almost surely, 2133050544300230 is an apocalyptic number.
133050544300230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133050544300230 is an abundant number, since it is smaller than the sum of its proper divisors (186270762020394).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133050544300230 is a wasteful number, since it uses less digits than its factorization.
133050544300230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4435018143351.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 133050544300230 its reverse (32003445050331), we get a palindrome (165053989350561).
The spelling of 133050544300230 in words is "one hundred thirty-three trillion, fifty billion, five hundred forty-four million, three hundred thousand, two hundred thirty".
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