Base | Representation |
---|---|
bin | 11110010000001011100010… |
… | …111111010100011111110010 |
3 | 122110002202211121022111212210 |
4 | 132100023202333110133302 |
5 | 114414421132104122310 |
6 | 1150551502231432550 |
7 | 40011532636213533 |
oct | 3620134277243762 |
9 | 573082747274783 |
10 | 133053305145330 |
11 | 39438654075619 |
12 | 12b0a756825756 |
13 | 5931b468190ab |
14 | 24bdb5874068a |
15 | 105b04d8ee820 |
hex | 7902e2fd47f2 |
133053305145330 has 32 divisors (see below), whose sum is σ = 319328346363264. Its totient is φ = 35480835370496.
The previous prime is 133053305145263. The next prime is 133053305145359. The reversal of 133053305145330 is 33541503350331.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25117282 + ... + 29949698.
It is an arithmetic number, because the mean of its divisors is an integer number (9979010823852).
Almost surely, 2133053305145330 is an apocalyptic number.
133053305145330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133053305145330 is an abundant number, since it is smaller than the sum of its proper divisors (186275041217934).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133053305145330 is a wasteful number, since it uses less digits than its factorization.
133053305145330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5750210.
The product of its (nonzero) digits is 364500, while the sum is 39.
Adding to 133053305145330 its reverse (33541503350331), we get a palindrome (166594808495661).
The spelling of 133053305145330 in words is "one hundred thirty-three trillion, fifty-three billion, three hundred five million, one hundred forty-five thousand, three hundred thirty".
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