Base | Representation |
---|---|
bin | 111101111101010110… |
… | …1001000101111001111 |
3 | 110201102211202012121022 |
4 | 1323322231020233033 |
5 | 4134444104431101 |
6 | 141042533424355 |
7 | 12420142105142 |
oct | 1737255105717 |
9 | 421384665538 |
10 | 133055155151 |
11 | 51479191446 |
12 | 21953a9b0bb |
13 | c715b2aa49 |
14 | 662314c059 |
15 | 36db19ea1b |
hex | 1efab48bcf |
133055155151 has 2 divisors, whose sum is σ = 133055155152. Its totient is φ = 133055155150.
The previous prime is 133055155069. The next prime is 133055155153. The reversal of 133055155151 is 151551550331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133055155151 is a prime.
Together with 133055155153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133055155153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66527577575 + 66527577576.
It is an arithmetic number, because the mean of its divisors is an integer number (66527577576).
Almost surely, 2133055155151 is an apocalyptic number.
133055155151 is a deficient number, since it is larger than the sum of its proper divisors (1).
133055155151 is an equidigital number, since it uses as much as digits as its factorization.
133055155151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28125, while the sum is 35.
The spelling of 133055155151 in words is "one hundred thirty-three billion, fifty-five million, one hundred fifty-five thousand, one hundred fifty-one".
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