Base | Representation |
---|---|
bin | 11000110010101010… |
… | …11011100000000111 |
3 | 1021100121000111212121 |
4 | 30121111123200013 |
5 | 204224321344314 |
6 | 10040422230411 |
7 | 650555464555 |
oct | 143125334007 |
9 | 37317014777 |
10 | 13309949959 |
11 | 5710135449 |
12 | 26b5585407 |
13 | 1341674647 |
14 | 9039acbd5 |
15 | 52d778d24 |
hex | 31955b807 |
13309949959 has 2 divisors, whose sum is σ = 13309949960. Its totient is φ = 13309949958.
The previous prime is 13309949957. The next prime is 13309949981. The reversal of 13309949959 is 95994990331.
It is a weak prime.
It is an emirp because it is prime and its reverse (95994990331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13309949959 - 21 = 13309949957 is a prime.
It is a super-3 number, since 3×133099499593 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 13309949957, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13309949897 and 13309949906.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13309949951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6654974979 + 6654974980.
It is an arithmetic number, because the mean of its divisors is an integer number (6654974980).
Almost surely, 213309949959 is an apocalyptic number.
13309949959 is a deficient number, since it is larger than the sum of its proper divisors (1).
13309949959 is an equidigital number, since it uses as much as digits as its factorization.
13309949959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10628820, while the sum is 61.
The spelling of 13309949959 in words is "thirteen billion, three hundred nine million, nine hundred forty-nine thousand, nine hundred fifty-nine".
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