Base | Representation |
---|---|
bin | 10011010111100101110… |
… | …110110000111110101001 |
3 | 11201020112202122021111212 |
4 | 103113211312300332221 |
5 | 133301342303431241 |
6 | 2455241543402505 |
7 | 165106310545664 |
oct | 23274566607651 |
9 | 4636482567455 |
10 | 1331001233321 |
11 | 473524551681 |
12 | 195b59753435 |
13 | 98688a3bb96 |
14 | 485c69826db |
15 | 249508c5beb |
hex | 135e5db0fa9 |
1331001233321 has 2 divisors, whose sum is σ = 1331001233322. Its totient is φ = 1331001233320.
The previous prime is 1331001233257. The next prime is 1331001233323. The reversal of 1331001233321 is 1233321001331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1306529011225 + 24472222096 = 1143035^2 + 156436^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331001233321 - 26 = 1331001233257 is a prime.
Together with 1331001233323, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1331001233323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665500616660 + 665500616661.
It is an arithmetic number, because the mean of its divisors is an integer number (665500616661).
Almost surely, 21331001233321 is an apocalyptic number.
It is an amenable number.
1331001233321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331001233321 is an equidigital number, since it uses as much as digits as its factorization.
1331001233321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1331001233321 its reverse (1233321001331), we get a palindrome (2564322234652).
The spelling of 1331001233321 in words is "one trillion, three hundred thirty-one billion, one million, two hundred thirty-three thousand, three hundred twenty-one".
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