Base | Representation |
---|---|
bin | 11000110010101100… |
… | …01000010000111111 |
3 | 1021100121100211101102 |
4 | 30121112020100333 |
5 | 204224343231221 |
6 | 10040430203315 |
7 | 650560160246 |
oct | 143126102077 |
9 | 37317324342 |
10 | 13310133311 |
11 | 5710250182 |
12 | 26b565353b |
13 | 1341709c37 |
14 | 903a1995d |
15 | 52d7b330b |
hex | 31958843f |
13310133311 has 2 divisors, whose sum is σ = 13310133312. Its totient is φ = 13310133310.
The previous prime is 13310133229. The next prime is 13310133313. The reversal of 13310133311 is 11333101331.
It is a strong prime.
It is an emirp because it is prime and its reverse (11333101331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13310133311 - 214 = 13310116927 is a prime.
It is a Sophie Germain prime.
Together with 13310133313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13310133313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655066655 + 6655066656.
It is an arithmetic number, because the mean of its divisors is an integer number (6655066656).
Almost surely, 213310133311 is an apocalyptic number.
13310133311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310133311 is an equidigital number, since it uses as much as digits as its factorization.
13310133311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 13310133311 its reverse (11333101331), we get a palindrome (24643234642).
The spelling of 13310133311 in words is "thirteen billion, three hundred ten million, one hundred thirty-three thousand, three hundred eleven".
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