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13310204317 is a prime number
BaseRepresentation
bin11000110010101100…
…11001100110011101
31021100121111102210021
430121112121212131
5204224403014232
610040431512141
7650560604254
oct143126314635
937317442707
1013310204317
115710299563
1226b5688651
131341733357
14903a3779b
1552d7c9397
hex31959999d

13310204317 has 2 divisors, whose sum is σ = 13310204318. Its totient is φ = 13310204316.

The previous prime is 13310204309. The next prime is 13310204359. The reversal of 13310204317 is 71340201331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12603654756 + 706549561 = 112266^2 + 26581^2 .

It is a cyclic number.

It is not a de Polignac number, because 13310204317 - 23 = 13310204309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13310204291 and 13310204300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13310204377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655102158 + 6655102159.

It is an arithmetic number, because the mean of its divisors is an integer number (6655102159).

Almost surely, 213310204317 is an apocalyptic number.

It is an amenable number.

13310204317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310204317 is an equidigital number, since it uses as much as digits as its factorization.

13310204317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 13310204317 its reverse (71340201331), we get a palindrome (84650405648).

The spelling of 13310204317 in words is "thirteen billion, three hundred ten million, two hundred four thousand, three hundred seventeen".