1331021311031 has 2 divisors, whose sum is σ = 1331021311032. Its totient is φ = 1331021311030.

The previous prime is 1331021310991. The next prime is 1331021311033. The reversal of 1331021311031 is 1301131201331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1331021311031 - 2¹⁰ = 1331021310007 is a prime.

It is a super-2 number, since 2×1331021311031² (a number of 25 digits) contains 22 as substring.

Together with 1331021311033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1331021310994 and 1331021311012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331021311033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665510655515 + 665510655516.

It is an arithmetic number, because the mean of its divisors is an integer number (665510655516).

Almost surely, 2^{1331021311031} is an apocalyptic number.

1331021311031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331021311031 is an equidigital number, since it uses as much as digits as its factorization.

1331021311031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1331021311031 its reverse (1301131201331), we get a palindrome (2632152512362).

The spelling of 1331021311031 in words is "one trillion, three hundred thirty-one billion, twenty-one million, three hundred eleven thousand, thirty-one".