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13310313127 is a prime number
BaseRepresentation
bin11000110010101101…
…10100001010100111
31021100121200222001021
430121112310022213
5204224420010002
610040434112011
7650561536426
oct143126641247
937317628037
1013310313127
115710363291
1226b571b607
131341770a37
14903a652bd
1552d7eb737
hex3195b42a7

13310313127 has 2 divisors, whose sum is σ = 13310313128. Its totient is φ = 13310313126.

The previous prime is 13310313059. The next prime is 13310313139. The reversal of 13310313127 is 72131301331.

13310313127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (72131301331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13310313127 - 27 = 13310312999 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13310310127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655156563 + 6655156564.

It is an arithmetic number, because the mean of its divisors is an integer number (6655156564).

Almost surely, 213310313127 is an apocalyptic number.

13310313127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310313127 is an equidigital number, since it uses as much as digits as its factorization.

13310313127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134, while the sum is 25.

Adding to 13310313127 its reverse (72131301331), we get a palindrome (85441614458).

The spelling of 13310313127 in words is "thirteen billion, three hundred ten million, three hundred thirteen thousand, one hundred twenty-seven".