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13310443103101 is a prime number
BaseRepresentation
bin1100000110110001010000…
…1110111010001101111101
31202010110120122222011022221
43001230110032322031331
53221034241413244401
644150422205405341
72542435121421544
oct301542416721575
952113518864287
1013310443103101
114271a22146a11
1215ab7a0569851
13757228227b71
1434032c0b115b
1518137da7d7a1
hexc1b143ba37d

13310443103101 has 2 divisors, whose sum is σ = 13310443103102. Its totient is φ = 13310443103100.

The previous prime is 13310443103063. The next prime is 13310443103131. The reversal of 13310443103101 is 10130134401331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11060746092900 + 2249697010201 = 3325770^2 + 1499899^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13310443103101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13310443103131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655221551550 + 6655221551551.

It is an arithmetic number, because the mean of its divisors is an integer number (6655221551551).

Almost surely, 213310443103101 is an apocalyptic number.

It is an amenable number.

13310443103101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310443103101 is an equidigital number, since it uses as much as digits as its factorization.

13310443103101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13310443103101 its reverse (10130134401331), we get a palindrome (23440577504432).

The spelling of 13310443103101 in words is "thirteen trillion, three hundred ten billion, four hundred forty-three million, one hundred three thousand, one hundred one".