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133110111111312 = 24319374073968501
BaseRepresentation
bin11110010001000000011100…
…111000111000100010010000
3122110022012110111202120122210
4132101000130320320202100
5114421334001421030222
61151033535120432120
740015613433026646
oct3621003470704220
9573265414676583
10133110111111312
113945a754604645
1212b1976aa78640
1359372ca61610a
1424c27c6d1d196
15105c775a31d0c
hex79101ce38890

133110111111312 has 160 divisors (see below), whose sum is σ = 371840614427520. Its totient is φ = 40888613376000.

The previous prime is 133110111111281. The next prime is 133110111111343. The reversal of 133110111111312 is 213111111011331.

It is an interprime number because it is at equal distance from previous prime (133110111111281) and next prime (133110111111343).

It is a super-2 number, since 2×1331101111113122 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 136955062 + ... + 137923562.

It is an arithmetic number, because the mean of its divisors is an integer number (2324003840172).

Almost surely, 2133110111111312 is an apocalyptic number.

133110111111312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133110111111312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (185920307213760).

133110111111312 is an abundant number, since it is smaller than the sum of its proper divisors (238730503316208).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133110111111312 is a wasteful number, since it uses less digits than its factorization.

133110111111312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 972641 (or 972635 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 21.

Adding to 133110111111312 its reverse (213111111011331), we get a palindrome (346221222122643).

The spelling of 133110111111312 in words is "one hundred thirty-three trillion, one hundred ten billion, one hundred eleven million, one hundred eleven thousand, three hundred twelve".

Divisors: 1 2 3 4 6 8 12 16 19 24 37 38 48 57 74 76 111 114 148 152 222 228 296 304 444 456 592 703 888 912 1406 1776 2109 2812 4073 4218 5624 8146 8436 11248 12219 16292 16872 24438 32584 33744 48876 65168 77387 97752 150701 154774 195504 232161 301402 309548 452103 464322 602804 619096 904206 928644 968501 1205608 1238192 1808412 1857288 1937002 2411216 2863319 2905503 3616824 3714576 3874004 5726638 5811006 7233648 7748008 8589957 11453276 11622012 15496016 17179914 18401519 22906552 23244024 34359828 35834537 36803038 45813104 46488048 55204557 68719656 71669074 73606076 107503611 110409114 137439312 143338148 147212152 215007222 220818228 286676296 294424304 430014444 441636456 573352592 680856203 860028888 883272912 1361712406 1720057776 2042568609 2723424812 3944704573 4085137218 5446849624 7889409146 8170274436 10893699248 11834113719 15778818292 16340548872 23668227438 31557636584 32681097744 47336454876 63115273168 74949386887 94672909752 145954069201 149898773774 189345819504 224848160661 291908138402 299797547548 437862207603 449696321322 583816276804 599595095096 875724415206 899392642644 1167632553608 1199190190192 1751448830412 1798785285288 2335265107216 2773127314819 3502897660824 3597570570576 5546254629638 7005795321648 8319381944457 11092509259276 16638763888914 22185018518552 33277527777828 44370037037104 66555055555656 133110111111312