Base | Representation |
---|---|
bin | 11110010001000001011110… |
… | …011101110110101100010010 |
3 | 122110022022022012000002011121 |
4 | 132101001132131312230102 |
5 | 114421343230044302010 |
6 | 1151034240222032454 |
7 | 40015652622461446 |
oct | 3621013635665422 |
9 | 573268265002147 |
10 | 133111211322130 |
11 | 39460169653288 |
12 | 12b19a1741872a |
13 | 593744453ba32 |
14 | 24c288d0b4826 |
15 | 105c7dc40a3da |
hex | 79105e776b12 |
133111211322130 has 32 divisors (see below), whose sum is σ = 241523561502720. Its totient is φ = 52817194160640.
The previous prime is 133111211322127. The next prime is 133111211322137. The reversal of 133111211322130 is 31223112111331.
It is a junction number, because it is equal to n+sod(n) for n = 133111211322095 and 133111211322104.
It is not an unprimeable number, because it can be changed into a prime (133111211322137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 369826 + ... + 16320514.
It is an arithmetic number, because the mean of its divisors is an integer number (7547611296960).
Almost surely, 2133111211322130 is an apocalyptic number.
133111211322130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133111211322130 is a deficient number, since it is larger than the sum of its proper divisors (108412350180590).
133111211322130 is a wasteful number, since it uses less digits than its factorization.
133111211322130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15957394.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 133111211322130 its reverse (31223112111331), we get a palindrome (164334323433461).
The spelling of 133111211322130 in words is "one hundred thirty-three trillion, one hundred eleven billion, two hundred eleven million, three hundred twenty-two thousand, one hundred thirty".
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