Base | Representation |
---|---|
bin | 1100000110110011110111… |
… | …1010001111111010111000 |
3 | 1202010112101101200120100222 |
4 | 3001230331322033322320 |
5 | 3221042204414030130 |
6 | 44151015424315212 |
7 | 2542461341643212 |
oct | 301547572177270 |
9 | 52115341616328 |
10 | 13311142330040 |
11 | 4272250908515 |
12 | 15ab956772b08 |
13 | 75730a056409 |
14 | 340396cc75b2 |
15 | 1813c014bce5 |
hex | c1b3de8feb8 |
13311142330040 has 64 divisors (see below), whose sum is σ = 30813485110560. Its totient is φ = 5173138206720.
The previous prime is 13311142330027. The next prime is 13311142330049. The reversal of 13311142330040 is 4003324111331.
It is a junction number, because it is equal to n+sod(n) for n = 13311142329991 and 13311142330009.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13311142330049) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33823841 + ... + 34215120.
Almost surely, 213311142330040 is an apocalyptic number.
13311142330040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13311142330040 is an abundant number, since it is smaller than the sum of its proper divisors (17502342780520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13311142330040 is a wasteful number, since it uses less digits than its factorization.
13311142330040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68039112 (or 68039108 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 13311142330040 its reverse (4003324111331), we get a palindrome (17314466441371).
The spelling of 13311142330040 in words is "thirteen trillion, three hundred eleven billion, one hundred forty-two million, three hundred thirty thousand, forty".
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