Base | Representation |
---|---|
bin | 111101111111000011… |
… | …0000110001110111100 |
3 | 110201120210202202102101 |
4 | 1323332012012032330 |
5 | 4140103134431030 |
6 | 141052324434444 |
7 | 12421432405345 |
oct | 1737606061674 |
9 | 421523682371 |
10 | 133112030140 |
11 | 514a82a8471 |
12 | 2196ab48a24 |
13 | c72485249b |
14 | 662a9150cc |
15 | 36e11867ca |
hex | 1efe1863bc |
133112030140 has 72 divisors (see below), whose sum is σ = 297522448272. Its totient is φ = 50015447040.
The previous prime is 133112030069. The next prime is 133112030147. The reversal of 133112030140 is 41030211331.
133112030140 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133112030147) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2989279 + ... + 3033481.
It is an arithmetic number, because the mean of its divisors is an integer number (4132256226).
Almost surely, 2133112030140 is an apocalyptic number.
133112030140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133112030140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (148761224136).
133112030140 is an abundant number, since it is smaller than the sum of its proper divisors (164410418132).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133112030140 is a wasteful number, since it uses less digits than its factorization.
133112030140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44767 (or 44748 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 133112030140 its reverse (41030211331), we get a palindrome (174142241471).
The spelling of 133112030140 in words is "one hundred thirty-three billion, one hundred twelve million, thirty thousand, one hundred forty".
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