Base | Representation |
---|---|
bin | 1100000110110100001100… |
… | …1000101100000010101000 |
3 | 1202010112121111122201202102 |
4 | 3001231003020230002220 |
5 | 3221042344340020240 |
6 | 44151032235352532 |
7 | 2542463455066466 |
oct | 301550310540250 |
9 | 52115544581672 |
10 | 13311230001320 |
11 | 4272296349219 |
12 | 15ab97bbb2748 |
13 | 757322271404 |
14 | 3403a47c9836 |
15 | 1813c7bb8815 |
hex | c1b4322c0a8 |
13311230001320 has 64 divisors (see below), whose sum is σ = 30996186829200. Its totient is φ = 5138706657280.
The previous prime is 13311230001317. The next prime is 13311230001359. The reversal of 13311230001320 is 2310003211331.
It can be written as a sum of positive squares in 8 ways, for example, as 7779335409316 + 5531894592004 = 2789146^2 + 2351998^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 13311230001292 and 13311230001301.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 299840 + ... + 5168400.
Almost surely, 213311230001320 is an apocalyptic number.
13311230001320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13311230001320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15498093414600).
13311230001320 is an abundant number, since it is smaller than the sum of its proper divisors (17684956827880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13311230001320 is a wasteful number, since it uses less digits than its factorization.
13311230001320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4870958 (or 4870954 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 13311230001320 its reverse (2310003211331), we get a palindrome (15621233212651).
The spelling of 13311230001320 in words is "thirteen trillion, three hundred eleven billion, two hundred thirty million, one thousand, three hundred twenty".
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