13311311003130 has 128 divisors (see below), whose sum is σ = 38526534144000. Its totient is φ = 2877598969344.

The previous prime is 13311311003099. The next prime is 13311311003161. The reversal of 13311311003130 is 3130011311331.

It is an interprime number because it is at equal distance from previous prime (13311311003099) and next prime (13311311003161).

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13311311003097 and 13311311003106.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15053080 + ... + 15912819.

It is an arithmetic number, because the mean of its divisors is an integer number (300988548000).

Almost surely, 2^{13311311003130} is an apocalyptic number.

13311311003130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13311311003130 is an abundant number, since it is smaller than the sum of its proper divisors (25215223140870).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311311003130 is a wasteful number, since it uses less digits than its factorization.

13311311003130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30966028.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 13311311003130 its reverse (3130011311331), we get a palindrome (16441322314461).

The spelling of 13311311003130 in words is "thirteen trillion, three hundred eleven billion, three hundred eleven million, three thousand, one hundred thirty".