Base | Representation |
---|---|
bin | 11000110010110101… |
… | …01100101100011100 |
3 | 1021100200121200102222 |
4 | 30121122230230130 |
5 | 204230200043400 |
6 | 10040512004512 |
7 | 650603306324 |
oct | 143132545434 |
9 | 37320550388 |
10 | 13311331100 |
11 | 5710999091 |
12 | 26b5b30738 |
13 | 1341a391a2 |
14 | 903c4c284 |
15 | 52d94d185 |
hex | 3196acb1c |
13311331100 has 18 divisors (see below), whose sum is σ = 28885588704. Its totient is φ = 5324532400.
The previous prime is 13311331097. The next prime is 13311331147. The reversal of 13311331100 is 113311331.
13311331100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 66556556 + ... + 66556755.
It is an arithmetic number, because the mean of its divisors is an integer number (1604754928).
Almost surely, 213311331100 is an apocalyptic number.
13311331100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13311331100 is an abundant number, since it is smaller than the sum of its proper divisors (15574257604).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13311331100 is a wasteful number, since it uses less digits than its factorization.
13311331100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 133113325 (or 133113318 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 13311331100 its reverse (113311331), we get a palindrome (13424642431).
The spelling of 13311331100 in words is "thirteen billion, three hundred eleven million, three hundred thirty-one thousand, one hundred".
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