13311341030 has 32 divisors (see below), whose sum is σ = 25842033504. Its totient is φ = 4907621376.

The previous prime is 13311341009. The next prime is 13311341033. The reversal of 13311341030 is 3014311331.

It is a super-2 number, since 2×13311341030² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13311340993 and 13311341011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311341033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11417 + ... + 163563.

It is an arithmetic number, because the mean of its divisors is an integer number (807563547).

Almost surely, 2^13311341030 is an apocalyptic number.

13311341030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13311341030 is a deficient number, since it is larger than the sum of its proper divisors (12530692474).

13311341030 is a wasteful number, since it uses less digits than its factorization.

13311341030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 152840.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 13311341030 its reverse (3014311331), we get a palindrome (16325652361).

The spelling of 13311341030 in words is "thirteen billion, three hundred eleven million, three hundred forty-one thousand, thirty".