Base | Representation |
---|---|
bin | 11000110010110101… |
… | …11110100000010010 |
3 | 1021100200202101111211 |
4 | 30121122332200102 |
5 | 204230204412200 |
6 | 10040513330334 |
7 | 650604032110 |
oct | 143132764022 |
9 | 37320671454 |
10 | 13311404050 |
11 | 5710a3897a |
12 | 26b5b669aa |
13 | 1341a63459 |
14 | 903c6aab0 |
15 | 52d964aba |
hex | 3196be812 |
13311404050 has 24 divisors (see below), whose sum is σ = 28296242496. Its totient is φ = 4563909840.
The previous prime is 13311404033. The next prime is 13311404081. The reversal of 13311404050 is 5040411331.
It is a super-3 number, since 3×133114040503 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 19015942 + ... + 19016641.
It is an arithmetic number, because the mean of its divisors is an integer number (1179010104).
Almost surely, 213311404050 is an apocalyptic number.
13311404050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13311404050 is an abundant number, since it is smaller than the sum of its proper divisors (14984838446).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13311404050 is a wasteful number, since it uses less digits than its factorization.
13311404050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38032602 (or 38032597 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 13311404050 its reverse (5040411331), we get a palindrome (18351815381).
The spelling of 13311404050 in words is "thirteen billion, three hundred eleven million, four hundred four thousand, fifty".
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