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133114134312120 = 2335132103277230059
BaseRepresentation
bin11110010001000100001100…
…101100001011010010111000
3122110022120211220010100122010
4132101010030230023102320
5114421420221340441440
61151035442235525520
740016115224463243
oct3621041454132270
9573276756110563
10133114134312120
11394614295a4995
1212b1a4b22b98a0
1359377bbc9bb00
1424c2a8939225a
15105c90dd3b580
hex79110cb0b4b8

133114134312120 has 384 divisors, whose sum is σ = 438200472153600. Its totient is φ = 32331151337472.

The previous prime is 133114134312109. The next prime is 133114134312151. The reversal of 133114134312120 is 21213431411331.

It is a happy number.

133114134312120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 578493651 + ... + 578723709.

It is an arithmetic number, because the mean of its divisors is an integer number (1141147062900).

Almost surely, 2133114134312120 is an apocalyptic number.

133114134312120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133114134312120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (219100236076800).

133114134312120 is an abundant number, since it is smaller than the sum of its proper divisors (305086337841480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133114134312120 is a wasteful number, since it uses less digits than its factorization.

133114134312120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 230479 (or 230462 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 133114134312120 its reverse (21213431411331), we get a palindrome (154327565723451).

The spelling of 133114134312120 in words is "one hundred thirty-three trillion, one hundred fourteen billion, one hundred thirty-four million, three hundred twelve thousand, one hundred twenty".