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13311430000997 is a prime number
BaseRepresentation
bin1100000110110100111100…
…0011101000000101100101
31202010120010102222202201212
43001231033003220011211
53221043302040012442
644151104142201205
72542501434053102
oct301551703500545
952116112882655
1013311430000997
114272389230a07
1215aba16b83205
1375735482850b
143403c31abaa9
151813da522a82
hexc1b4f0e8165

13311430000997 has 2 divisors, whose sum is σ = 13311430000998. Its totient is φ = 13311430000996.

The previous prime is 13311430000993. The next prime is 13311430001017. The reversal of 13311430000997 is 79900003411331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9649683683236 + 3661746317761 = 3106394^2 + 1913569^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311430000997 - 22 = 13311430000993 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311430000993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655715000498 + 6655715000499.

It is an arithmetic number, because the mean of its divisors is an integer number (6655715000499).

Almost surely, 213311430000997 is an apocalyptic number.

It is an amenable number.

13311430000997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311430000997 is an equidigital number, since it uses as much as digits as its factorization.

13311430000997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61236, while the sum is 41.

The spelling of 13311430000997 in words is "thirteen trillion, three hundred eleven billion, four hundred thirty million, nine hundred ninety-seven", and thus it is an aban number.