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13311430001017 is a prime number
BaseRepresentation
bin1100000110110100111100…
…0011101000000101111001
31202010120010102222202202121
43001231033003220011321
53221043302040013032
644151104142201241
72542501434053131
oct301551703500571
952116112882677
1013311430001017
114272389230a25
1215aba16b83221
13757354828525
143403c31abac1
151813da522a97
hexc1b4f0e8179

13311430001017 has 2 divisors, whose sum is σ = 13311430001018. Its totient is φ = 13311430001016.

The previous prime is 13311430000997. The next prime is 13311430001029. The reversal of 13311430001017 is 71010003411331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13144184991081 + 167245009936 = 3625491^2 + 408956^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13311430001017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13311430000982 and 13311430001000.

It is not a weakly prime, because it can be changed into another prime (13311430001047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655715000508 + 6655715000509.

It is an arithmetic number, because the mean of its divisors is an integer number (6655715000509).

Almost surely, 213311430001017 is an apocalyptic number.

It is an amenable number.

13311430001017 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311430001017 is an equidigital number, since it uses as much as digits as its factorization.

13311430001017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 13311430001017 its reverse (71010003411331), we get a palindrome (84321433412348).

The spelling of 13311430001017 in words is "thirteen trillion, three hundred eleven billion, four hundred thirty million, one thousand, seventeen".