13311430011031 has 2 divisors, whose sum is σ = 13311430011032. Its totient is φ = 13311430011030.

The previous prime is 13311430011029. The next prime is 13311430011067. The reversal of 13311430011031 is 13011003411331.

13311430011031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13311430011031 - 2¹ = 13311430011029 is a prime.

It is a super-3 number, since 3×13311430011031³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13311430011029, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13311430010993 and 13311430011011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311430011091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655715005515 + 6655715005516.

It is an arithmetic number, because the mean of its divisors is an integer number (6655715005516).

Almost surely, 2^{13311430011031} is an apocalyptic number.

13311430011031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311430011031 is an equidigital number, since it uses as much as digits as its factorization.

13311430011031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 13311430011031 its reverse (13011003411331), we get a palindrome (26322433422362).

The spelling of 13311430011031 in words is "thirteen trillion, three hundred eleven billion, four hundred thirty million, eleven thousand, thirty-one".