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13311683840 = 285713259149
BaseRepresentation
bin11000110010111000…
…00010110100000000
31021100201021121022102
430121130002310000
5204230242340330
610040523325532
7650606305610
oct143134026400
937321247272
1013311683840
11571110a104
1226b60808a8
131341b30900
14903d00a40
1552d9bc945
hex319702d00

13311683840 has 432 divisors, whose sum is σ = 40397616000. Its totient is φ = 4113727488.

The previous prime is 13311683837. The next prime is 13311683857. The reversal of 13311683840 is 4838611331.

It is a super-2 number, since 2×133116838402 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13311683794 and 13311683803.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 89340086 + ... + 89340234.

It is an arithmetic number, because the mean of its divisors is an integer number (93513000).

Almost surely, 213311683840 is an apocalyptic number.

13311683840 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311683840, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20198808000).

13311683840 is an abundant number, since it is smaller than the sum of its proper divisors (27085932160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311683840 is a wasteful number, since it uses less digits than its factorization.

13311683840 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 262 (or 235 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 13311683840 in words is "thirteen billion, three hundred eleven million, six hundred eighty-three thousand, eight hundred forty".