Base | Representation |
---|---|
bin | 1100000110110111010111… |
… | …0010011001100101100111 |
3 | 1202010121210201200210201001 |
4 | 3001231311302121211213 |
5 | 3221101114411442313 |
6 | 44151252433414131 |
7 | 2542523514165631 |
oct | 301556562314547 |
9 | 52117721623631 |
10 | 13312079796583 |
11 | 4272691aaaa57 |
12 | 15abb7870a347 |
13 | 75742933a449 |
14 | 3404455d7a51 |
15 | 1814275c9add |
hex | c1b75c99967 |
13312079796583 has 2 divisors, whose sum is σ = 13312079796584. Its totient is φ = 13312079796582.
The previous prime is 13312079796577. The next prime is 13312079796629. The reversal of 13312079796583 is 38569797021331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13312079796583 is a prime.
It is a super-2 number, since 2×133120797965832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13312079796503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656039898291 + 6656039898292.
It is an arithmetic number, because the mean of its divisors is an integer number (6656039898292).
Almost surely, 213312079796583 is an apocalyptic number.
13312079796583 is a deficient number, since it is larger than the sum of its proper divisors (1).
13312079796583 is an equidigital number, since it uses as much as digits as its factorization.
13312079796583 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51438240, while the sum is 64.
The spelling of 13312079796583 in words is "thirteen trillion, three hundred twelve billion, seventy-nine million, seven hundred ninety-six thousand, five hundred eighty-three".
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