Base | Representation |
---|---|
bin | 10011010111110010010… |
… | …111110011100010001010 |
3 | 11201021002101202202122010 |
4 | 103113302113303202022 |
5 | 133302310033034010 |
6 | 2455314444240350 |
7 | 165114440452230 |
oct | 23276227634212 |
9 | 4637071682563 |
10 | 1331211221130 |
11 | 47362203661a |
12 | 195bb7b400b6 |
13 | 986c03b231b |
14 | 48606804950 |
15 | 24964054620 |
hex | 135f25f388a |
1331211221130 has 32 divisors (see below), whose sum is σ = 3651322207104. Its totient is φ = 304276850496.
The previous prime is 1331211221083. The next prime is 1331211221159. The reversal of 1331211221130 is 311221121331.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 1331211221097 and 1331211221106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3169550317 + ... + 3169550736.
It is an arithmetic number, because the mean of its divisors is an integer number (114103818972).
Almost surely, 21331211221130 is an apocalyptic number.
1331211221130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1331211221130 is an abundant number, since it is smaller than the sum of its proper divisors (2320110985974).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1331211221130 is a wasteful number, since it uses less digits than its factorization.
1331211221130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6339101070.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1331211221130 its reverse (311221121331), we get a palindrome (1642432342461).
The spelling of 1331211221130 in words is "one trillion, three hundred thirty-one billion, two hundred eleven million, two hundred twenty-one thousand, one hundred thirty".
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