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133121426050511 is a prime number
BaseRepresentation
bin11110010001001010111111…
…010011111100110111001111
3122110100021200001211001020222
4132101022333103330313033
5114422030140032104021
61151043045555101555
740016464015312613
oct3621127723746717
9573307601731228
10133121426050511
113946453059a968
1212b1b9a82a18bb
1359383b186c302
1424c317b971343
15105cbd90816ab
hex7912bf4fcdcf

133121426050511 has 2 divisors, whose sum is σ = 133121426050512. Its totient is φ = 133121426050510.

The previous prime is 133121426050321. The next prime is 133121426050517. The reversal of 133121426050511 is 115050624121331.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133121426050511 - 214 = 133121426034127 is a prime.

It is a super-3 number, since 3×1331214260505113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133121426050517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560713025255 + 66560713025256.

It is an arithmetic number, because the mean of its divisors is an integer number (66560713025256).

Almost surely, 2133121426050511 is an apocalyptic number.

133121426050511 is a deficient number, since it is larger than the sum of its proper divisors (1).

133121426050511 is an equidigital number, since it uses as much as digits as its factorization.

133121426050511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 133121426050511 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, four hundred twenty-six million, fifty thousand, five hundred eleven".