Base | Representation |
---|---|
bin | 11110010001001010111111… |
… | …010011111100110111001111 |
3 | 122110100021200001211001020222 |
4 | 132101022333103330313033 |
5 | 114422030140032104021 |
6 | 1151043045555101555 |
7 | 40016464015312613 |
oct | 3621127723746717 |
9 | 573307601731228 |
10 | 133121426050511 |
11 | 3946453059a968 |
12 | 12b1b9a82a18bb |
13 | 59383b186c302 |
14 | 24c317b971343 |
15 | 105cbd90816ab |
hex | 7912bf4fcdcf |
133121426050511 has 2 divisors, whose sum is σ = 133121426050512. Its totient is φ = 133121426050510.
The previous prime is 133121426050321. The next prime is 133121426050517. The reversal of 133121426050511 is 115050624121331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133121426050511 - 214 = 133121426034127 is a prime.
It is a super-3 number, since 3×1331214260505113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133121426050517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560713025255 + 66560713025256.
It is an arithmetic number, because the mean of its divisors is an integer number (66560713025256).
Almost surely, 2133121426050511 is an apocalyptic number.
133121426050511 is a deficient number, since it is larger than the sum of its proper divisors (1).
133121426050511 is an equidigital number, since it uses as much as digits as its factorization.
133121426050511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 35.
The spelling of 133121426050511 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, four hundred twenty-six million, fifty thousand, five hundred eleven".
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