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1331221221133 is a prime number
BaseRepresentation
bin10011010111110010111…
…101111100111100001101
311201021010002120211001121
4103113302331330330031
5133302320113034013
62455315442440541
7165114621451606
oct23276275747415
94637102524047
101331221221133
11473627746791
12195bbb363151
13986c24a3b9b
1448607c88dad
1524964d7c58d
hex135f2f7cf0d

1331221221133 has 2 divisors, whose sum is σ = 1331221221134. Its totient is φ = 1331221221132.

The previous prime is 1331221221089. The next prime is 1331221221139. The reversal of 1331221221133 is 3311221221331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 907260060004 + 423961161129 = 952502^2 + 651123^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331221221133 - 217 = 1331221090061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1331221221098 and 1331221221107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331221221139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665610610566 + 665610610567.

It is an arithmetic number, because the mean of its divisors is an integer number (665610610567).

Almost surely, 21331221221133 is an apocalyptic number.

It is an amenable number.

1331221221133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331221221133 is an equidigital number, since it uses as much as digits as its factorization.

1331221221133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 25.

Adding to 1331221221133 its reverse (3311221221331), we get a palindrome (4642442442464).

The spelling of 1331221221133 in words is "one trillion, three hundred thirty-one billion, two hundred twenty-one million, two hundred twenty-one thousand, one hundred thirty-three".