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13312213301117 is a prime number
BaseRepresentation
bin1100000110110111110110…
…1111101011011101111101
31202010122011000220112111102
43001231331233223131331
53221101403101113432
644151314003102445
72542530025023653
oct301557557533575
952118130815442
1013312213301117
1142727503a5985
1215abbb5371a25
1375744abb2103
1434045922add3
1518143419b962
hexc1b7dbeb77d

13312213301117 has 2 divisors, whose sum is σ = 13312213301118. Its totient is φ = 13312213301116.

The previous prime is 13312213301081. The next prime is 13312213301147. The reversal of 13312213301117 is 71110331221331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12234646813636 + 1077566487481 = 3497806^2 + 1038059^2 .

It is a cyclic number.

It is not a de Polignac number, because 13312213301117 - 210 = 13312213300093 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13312213301117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13312213301147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656106650558 + 6656106650559.

It is an arithmetic number, because the mean of its divisors is an integer number (6656106650559).

Almost surely, 213312213301117 is an apocalyptic number.

It is an amenable number.

13312213301117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312213301117 is an equidigital number, since it uses as much as digits as its factorization.

13312213301117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2268, while the sum is 29.

Adding to 13312213301117 its reverse (71110331221331), we get a palindrome (84422544522448).

The spelling of 13312213301117 in words is "thirteen trillion, three hundred twelve billion, two hundred thirteen million, three hundred one thousand, one hundred seventeen".