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13312213301147 is a prime number
BaseRepresentation
bin1100000110110111110110…
…1111101011011110011011
31202010122011000220112112112
43001231331233223132123
53221101403101114042
644151314003102535
72542530025024025
oct301557557533633
952118130815475
1013312213301147
1142727503a5a02
1215abbb5371a4b
1375744abb2127
1434045922b015
1518143419b982
hexc1b7dbeb79b

13312213301147 has 2 divisors, whose sum is σ = 13312213301148. Its totient is φ = 13312213301146.

The previous prime is 13312213301117. The next prime is 13312213301171. The reversal of 13312213301147 is 74110331221331.

It is a strong prime.

It is an emirp because it is prime and its reverse (74110331221331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13312213301147 - 224 = 13312196523931 is a prime.

It is not a weakly prime, because it can be changed into another prime (13312213301117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656106650573 + 6656106650574.

It is an arithmetic number, because the mean of its divisors is an integer number (6656106650574).

Almost surely, 213312213301147 is an apocalyptic number.

13312213301147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312213301147 is an equidigital number, since it uses as much as digits as its factorization.

13312213301147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 32.

Adding to 13312213301147 its reverse (74110331221331), we get a palindrome (87422544522478).

The spelling of 13312213301147 in words is "thirteen trillion, three hundred twelve billion, two hundred thirteen million, three hundred one thousand, one hundred forty-seven".