Base | Representation |
---|---|
bin | 10011010111110011010… |
… | …101110100110101100101 |
3 | 11201021010112100202210011 |
4 | 103113303111310311211 |
5 | 133302323213320042 |
6 | 2455320224530221 |
7 | 165115025605354 |
oct | 23276325646545 |
9 | 4637115322704 |
10 | 1331227479397 |
11 | 473630230702 |
12 | 196001480971 |
13 | 986c38855ba |
14 | 48608a3799b |
15 | 249656b6a17 |
hex | 135f3574d65 |
1331227479397 has 2 divisors, whose sum is σ = 1331227479398. Its totient is φ = 1331227479396.
The previous prime is 1331227479391. The next prime is 1331227479457. The reversal of 1331227479397 is 7939747221331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1317734101476 + 13493377921 = 1147926^2 + 116161^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331227479397 - 219 = 1331226955109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331227479391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665613739698 + 665613739699.
It is an arithmetic number, because the mean of its divisors is an integer number (665613739699).
Almost surely, 21331227479397 is an apocalyptic number.
It is an amenable number.
1331227479397 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331227479397 is an equidigital number, since it uses as much as digits as its factorization.
1331227479397 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12002256, while the sum is 58.
The spelling of 1331227479397 in words is "one trillion, three hundred thirty-one billion, two hundred twenty-seven million, four hundred seventy-nine thousand, three hundred ninety-seven".
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