Base | Representation |
---|---|
bin | 1111110111101… |
… | …10011011101111 |
3 | 100021111200222112 |
4 | 13323312123233 |
5 | 233040124332 |
6 | 21113234235 |
7 | 3204405005 |
oct | 773663357 |
9 | 307450875 |
10 | 133129967 |
11 | 6916a573 |
12 | 3870297b |
13 | 21773339 |
14 | 13976a75 |
15 | ba4adb2 |
hex | 7ef66ef |
133129967 has 2 divisors, whose sum is σ = 133129968. Its totient is φ = 133129966.
The previous prime is 133129961. The next prime is 133129973. The reversal of 133129967 is 769921331.
It is a balanced prime because it is at equal distance from previous prime (133129961) and next prime (133129973).
It is an emirp because it is prime and its reverse (769921331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133129967 - 24 = 133129951 is a prime.
It is a super-2 number, since 2×1331299672 = 35447176226842178, which contains 22 as substring.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133129961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66564983 + 66564984.
It is an arithmetic number, because the mean of its divisors is an integer number (66564984).
Almost surely, 2133129967 is an apocalyptic number.
133129967 is a deficient number, since it is larger than the sum of its proper divisors (1).
133129967 is an equidigital number, since it uses as much as digits as its factorization.
133129967 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 61236, while the sum is 41.
The square root of 133129967 is about 11538.1960028420. The cubic root of 133129967 is about 510.6130868641.
The spelling of 133129967 in words is "one hundred thirty-three million, one hundred twenty-nine thousand, nine hundred sixty-seven".
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