133131001121130 has 16 divisors (see below), whose sum is σ = 319514402690784. Its totient is φ = 35501600298960.

The previous prime is 133131001121089. The next prime is 133131001121141. The reversal of 133131001121130 is 31121100131331.

It is a junction number, because it is equal to n+sod(n) for n = 133131001121097 and 133131001121106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2218850018656 + ... + 2218850018715.

It is an arithmetic number, because the mean of its divisors is an integer number (19969650168174).

Almost surely, 2^{133131001121130} is an apocalyptic number.

133131001121130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133131001121130 is an abundant number, since it is smaller than the sum of its proper divisors (186383401569654).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133131001121130 is a wasteful number, since it uses less digits than its factorization.

133131001121130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4437700037381.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 133131001121130 its reverse (31121100131331), we get a palindrome (164252101252461).

The spelling of 133131001121130 in words is "one hundred thirty-three trillion, one hundred thirty-one billion, one million, one hundred twenty-one thousand, one hundred thirty".