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133131332220181 is a prime number
BaseRepresentation
bin11110010001010100001101…
…110000111111010100010101
3122110101020020110000121100221
4132101110031300333110111
5114422210432022021211
61151051404550434341
740020264343340011
oct3621241560772425
9573336213017327
10133131332220181
1139468754347849
1212b218b19629b1
1359392ccc96279
1424c383b46b541
15105d0b8aa7c71
hex79150dc3f515

133131332220181 has 2 divisors, whose sum is σ = 133131332220182. Its totient is φ = 133131332220180.

The previous prime is 133131332220169. The next prime is 133131332220221. The reversal of 133131332220181 is 181022233131331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83953861817956 + 49177470402225 = 9162634^2 + 7012665^2 .

It is a cyclic number.

It is not a de Polignac number, because 133131332220181 - 225 = 133131298665749 is a prime.

It is a super-3 number, since 3×1331313322201813 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133131332220151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66565666110090 + 66565666110091.

It is an arithmetic number, because the mean of its divisors is an integer number (66565666110091).

Almost surely, 2133131332220181 is an apocalyptic number.

It is an amenable number.

133131332220181 is a deficient number, since it is larger than the sum of its proper divisors (1).

133131332220181 is an equidigital number, since it uses as much as digits as its factorization.

133131332220181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 34.

The spelling of 133131332220181 in words is "one hundred thirty-three trillion, one hundred thirty-one billion, three hundred thirty-two million, two hundred twenty thousand, one hundred eighty-one".