Base | Representation |
---|---|
bin | 1100000110111110101010… |
… | …1000011110111010101001 |
3 | 1202010210212100102010022101 |
4 | 3001233222220132322221 |
5 | 3221114123233144431 |
6 | 44152215142253401 |
7 | 2542623216565213 |
oct | 301575250367251 |
9 | 52123770363271 |
10 | 13314040131241 |
11 | 42734a8615443 |
12 | 15b0425127261 |
13 | 75767c507395 |
14 | 34058dac95b3 |
15 | 1814de754961 |
hex | c1beaa1eea9 |
13314040131241 has 2 divisors, whose sum is σ = 13314040131242. Its totient is φ = 13314040131240.
The previous prime is 13314040131221. The next prime is 13314040131253. The reversal of 13314040131241 is 14213104041331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9376609515625 + 3937430615616 = 3062125^2 + 1984296^2 .
It is a cyclic number.
It is not a de Polignac number, because 13314040131241 - 215 = 13314040098473 is a prime.
It is not a weakly prime, because it can be changed into another prime (13314040131221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6657020065620 + 6657020065621.
It is an arithmetic number, because the mean of its divisors is an integer number (6657020065621).
Almost surely, 213314040131241 is an apocalyptic number.
It is an amenable number.
13314040131241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13314040131241 is an equidigital number, since it uses as much as digits as its factorization.
13314040131241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 13314040131241 its reverse (14213104041331), we get a palindrome (27527144172572).
The spelling of 13314040131241 in words is "thirteen trillion, three hundred fourteen billion, forty million, one hundred thirty-one thousand, two hundred forty-one".
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