13314040131253 has 2 divisors, whose sum is σ = 13314040131254. Its totient is φ = 13314040131252.

The previous prime is 13314040131241. The next prime is 13314040131347. The reversal of 13314040131253 is 35213104041331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11496283640689 + 1817756490564 = 3390617^2 + 1348242^2 .

It is a cyclic number.

It is not a de Polignac number, because 13314040131253 - 2⁵ = 13314040131221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13312040131253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6657020065626 + 6657020065627.

It is an arithmetic number, because the mean of its divisors is an integer number (6657020065627).

Almost surely, 2^{13314040131253} is an apocalyptic number.

It is an amenable number.

13314040131253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13314040131253 is an equidigital number, since it uses as much as digits as its factorization.

13314040131253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 13314040131253 its reverse (35213104041331), we get a palindrome (48527144172584).

The spelling of 13314040131253 in words is "thirteen trillion, three hundred fourteen billion, forty million, one hundred thirty-one thousand, two hundred fifty-three".