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1331411351 is a prime number
BaseRepresentation
bin100111101011011…
…1011100110010111
310102210021201000112
41033112323212113
510211320130401
6340040433235
744664544514
oct11726734627
93383251015
101331411351
11623602066
12311a7881b
13182ab548a
14c8b7a30b
157bd473bb
hex4f5bb997

1331411351 has 2 divisors, whose sum is σ = 1331411352. Its totient is φ = 1331411350.

The previous prime is 1331411317. The next prime is 1331411353. The reversal of 1331411351 is 1531141331.

It is a strong prime.

It is an emirp because it is prime and its reverse (1531141331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1331411351 is a prime.

Together with 1331411353, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331411353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665705675 + 665705676.

It is an arithmetic number, because the mean of its divisors is an integer number (665705676).

Almost surely, 21331411351 is an apocalyptic number.

1331411351 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331411351 is an equidigital number, since it uses as much as digits as its factorization.

1331411351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 540, while the sum is 23.

The square root of 1331411351 is about 36488.5098489922. The cubic root of 1331411351 is about 1100.1133081627.

Adding to 1331411351 its reverse (1531141331), we get a palindrome (2862552682).

The spelling of 1331411351 in words is "one billion, three hundred thirty-one million, four hundred eleven thousand, three hundred fifty-one".