Base | Representation |
---|---|
bin | 111110000000000000… |
… | …1010100011100001111 |
3 | 110201200001112212022022 |
4 | 1330000001110130033 |
5 | 4140134422111142 |
6 | 141055441040355 |
7 | 12422304102116 |
oct | 1740001243417 |
9 | 421601485268 |
10 | 133144332047 |
11 | 51514560361 |
12 | 219799260bb |
13 | c72b45213c |
14 | 6630d22c7d |
15 | 36e3e176d2 |
hex | 1f0005470f |
133144332047 has 2 divisors, whose sum is σ = 133144332048. Its totient is φ = 133144332046.
The previous prime is 133144332011. The next prime is 133144332071. The reversal of 133144332047 is 740233441331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133144332047 - 214 = 133144315663 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133144331998 and 133144332016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133144332247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66572166023 + 66572166024.
It is an arithmetic number, because the mean of its divisors is an integer number (66572166024).
Almost surely, 2133144332047 is an apocalyptic number.
133144332047 is a deficient number, since it is larger than the sum of its proper divisors (1).
133144332047 is an equidigital number, since it uses as much as digits as its factorization.
133144332047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 35.
Adding to 133144332047 its reverse (740233441331), we get a palindrome (873377773378).
The spelling of 133144332047 in words is "one hundred thirty-three billion, one hundred forty-four million, three hundred thirty-two thousand, forty-seven".
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